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Anonymous

Dec 31, 2024

2 C6H14 + 19 O2 –> 12 CO2 + 14 H2O

What is the balanced chemical equation for the combustion of hexane (C6H14) in the presence of oxygen (O2), resulting in the formation of carbon dioxide (CO2) and water (H2O)? The equation is as follows:

2 C6H14 + 19 O2 → 12 CO2 + 14 H2O.

Can you explain the significance of this reaction in terms of energy release and its applications?

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3 Answers

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Anonymous

Oct 29, 2024

4.06 mol H₂OExplanation:2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O First we convert the given masses of reactants into moles, using their respective molar masses:250 g O₂ ÷ 32 g/mol = 7.81 mol O₂50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄Now we calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles, using the stoichiometric coefficients of the reaction:0.58 mol C₆H₁₄ * = 5.51 mol O₂As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that C₆H₁₄ is the limiting reactant. Now we can calculate how much water can be formed, using the number of moles of the limiting reactant:0.58 mol C₆H₁₄ * = 4.06 mol H₂O
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A
Anonymous

Feb 21, 2025

no podemos ver la explanation: no te podemos ayudar: /
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