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A

Anonymous

Dec 06, 2024

What is the mass of 8.50×10^22 molecules of NH3?

I’m having difficulty solving the problem regarding the mass of 8.50 × 10²² molecules of NH₃ (ammonia). Could someone please explain how to approach this? Specifically, I would like guidance on the conversion factors I need to use. I’m studying for a test, and I would really appreciate any help!

4 Answers

A
Anonymous

Feb 22, 2025

You would use Avagadro’s number (6.02×10^23) to solve this. Here’s how:

8.50×10^22 molecules of NH3 x 1 mole of NH3/6.02×10^23 molecules of NH3 = 0.14 moles

Then you convert from moles to grams. First we need the molecular mass of NH3. Nitrogen’s weight is about 14 and hydrogens is about 1, but we have three hydrogens so we multiply 1×3=3. We add 14 and 3 to give us 17 grams per mole for NH3. Now we take this number to do our conversion:

0.14 moles of NH3 x 17 grams/mole = 2.38 grams of NH3

I’ve done some rounding, so be aware of that.

A
Anonymous

Feb 20, 2025

well divide that by 6.022×10^23 atoms (which is the amount of things in a mol)

to get how many mols of NH3

then multiply the mols by the molecular mass (14g+1x3g per mol of NH3)

to get the mass of 8.50×10^22 molecules of NH3

i got about 2.4 grams

u can do significant figures by calculating with more precise molar masses

A
Anonymous

Feb 20, 2025

use Avogadro’s as the conversion factor.

it is the number of molecules in one gram mole = 6.022*10^23

Molecular mass of NH3 = 17g/mole which contains Avogdro’s number of molecules

17*8.50×10^22/6.022*10^23 = 24*10^(22-23) = 2.4g

Use Avogadro.

Avogadro’s #, 6.022×10^23, is the # of atoms or molecules in 1 mole of anything.

Hence if you want to find out how many molecules is so many moles of something, you put Avogadro’s # on the bottom (Denominator). If you want to find moles, you put it on the top (numerator) of the fraction.

Here’s some examples:

Find how many atoms in 4.398 moles H2

H2 is a diatomic molecule, so you use molecules, then multiply by 2 to get atoms, because there are 2 atoms/molecule.

Set up: what you have, X (Avogadro’s #) (atoms/molecule)

Hence: 4.398 mols H2 (6.022×10^23 molecules/1mol) = your answer, because moles cancel out.

math: 4.398* 6.022×10^23 = 2.65×10^24 molecules (2atoms/1molecule) = 5.3×10^24 atoms

Find mols 8.3×10^18 atoms Mg

8.3×10^18atoms (1mol/6.022×10^23 atoms) = mol Mg

math: 8.3×10^18/6.022×10^23 = 1.35×10^-5, or 0.0000135mol Mg

Easy, huh?

Hope this helps, good luck on your test!

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