What is wrong with this batch file code?

Question

Here is the code:
batch
@ECHO ON
set drive=%cd:~0,3%
xcopy *.jpg “%drive%folder” /s /y /q
xcopy *.jpeg “%drive%folder” /s /y /q
I'm trying to copy all JPEG files to a folder named “folder” located on the F drive. The folder exists, so I am unsure why I am receiving an error. Can anyone help me troubleshoot this issue? Additionally, is there a command that I can use to create a folder if it doesn't already exist? Thank you!

Anonymous · Accepted Answer

This command:
set drive=%cd:~0,3%
get THREE characters of the directory; for example F:
When you put %drive%folder there are two back-slash characters: F:folder
use set drive=%cd:~0,2% or omit the  in xcopy’s: %drive%folder
Also, the quotes should enclose just the folder name, not the switches:
xcopy *.jpg “%drive%folder” /s /y /q
Regards…
—————————————————————-
EDIT:
The cause: I bet you start your Batch file in a folder located INSIDE or in THE SAME “%drive%folder”. You can’t do that!
The explanation: When you use /S switch in xcopy, the source files must be in a folder in ABOVE LEVEL with respect to the destination; otherwise, after created a folder and copy it, the process should go into this folder and copy it again in a never-ending process.
Regards…

Anonymous · Answer

https://shorturl.im/rT0wI
the big problem I see is that you can’t multiply floating point numbers in batch. in other words, you can only multiply integers. example: set weight=%userin%*”0.454″ You have 0.454 being multiplied by another number. Can’t be done in dos. BUT… if you wanted to multiply 454 buy it, and then at the end divide by 1000, you could do that. But there’s another thing wrong with your code: set weight=%userin%*”0.454″ should be: set /a weight=%userin% * 454 Don’t forget to include the /a.

Laurine Denesik · Answer

Cannot Perform A Cyclic Copy

Anonymous

What is wrong with this batch file code?

3 Answers

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