Find f. f ”(x) = x^−2, x > 0, f(1) = 0, f(8) = 0?
I am trying to find the function ( f ) given that ( f''(x) = x^{-2} ) for ( x > 0 ), with the conditions ( f(1) = 0 ) and ( f(8) = 0 ). My current solution is ( f(x) = -\ln(x) + ( \ln(8) ) x - \ln(8) ), but it appears that this is incorrect. Can anyone provide guidance on how to approach this problem correctly? Thank you!
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