Given that an = 3an – 1 + 1, where a1 = 2, find the 3rd-6th terms of the sequence.
Given the recurrence relation for the sequence defined as ( a_n = 3a_{n-1} + 1 ), where ( a_1 = 2 ), please find the 3rd to 6th terms of the sequence.
A) 2, 7, 22, 67 B) 7, 22, 67, 202 C) 22, 67, 202, 607 D) 67, 202, 607, 1822
Thank you!
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