How do you find standard deviation for a paired difference test?
How do you find the standard deviation for a paired difference test?
My teacher provided an example related to this type of problem. The scenario involves working in Human Resources and assessing whether there is a difference in test scores after a training program. The sample consists of four pairs of scores:
Before: - Sam: 85 - Tamika: 94 - Brian: 78 - Mike: 87
After: - Sam: 94 - Tamika: 87 - Brian: 79 - Mike: 88
The calculated standard deviation for this data set was 6.53. I already understand how to find the mean and degrees of freedom. Could someone please assist me in calculating the standard deviation? Thank you!
5 Answers
Before After Difference
Sam 85 94 9
Tamika 94 87 -7
Brian 78 79 2
Mike 87 88 1
Mean difference = (9-7+2+1)/4 = 1.25
Var =sum[(diff-mean diff)^2] / 3
= [(9-1.25)^2 + (-7-1.25)^2 + (2-1.25)^2 + (1-1.25)^2] / 3
= 128.75/3
= 42.92
SD = sqrt(Var) = sqrt(42.92) = 6.55
Feb 21, 2025
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RE:
How do you find standard deviation for a paired difference test?
My teacher gave an example for this kind of problem. The problem states that you work in Human Resources and you are trying to see if there is a difference in test scores after a training program. There are four pairs for the sample
Before After
Sam 85 …
A. √[(40-45.8)²+(38-45.8)²+(57-45.8)²+(53… /5 =√58.96… std= 7.67 B. √[(38-36.8)²+(34-36.8)²+(35-36.8)²+(45… /5 =√20.56… std= 4.53 I believe these to be the correct answers. It is hard to explain how to do it really, but I suggest you consult wikipedia if you want to know how to use the formula. Edit: err, it appears the poster above me got a different answer than I did. I am only in introductory stats, but still, I believe I did my answer correctly, especially because the internet has std solvers, and my answers checked. Edit again: Ya thats right, I remember hearing about that, but of course I forgot.. (so much to remember!). To Blahb: Nice catch on that, I would expect nothing less from a prof though ?
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