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A

Anonymous

Jan 22, 2025

Physics question…. help?

An archer shoots an arrow horizontally at a target located 15 meters away. Although the arrow is aimed directly at the center of the target, it strikes the target 48 centimeters lower than intended. What was the initial speed of the arrow, assuming air resistance is negligible? Please provide your answer in meters per second (m/s).

1 Answers

A
Anonymous

Nov 20, 2024

Find flight time:

0.48 = (1/2) g t^2

t= sqr(2*0.48/9.8) = 0.31298 s

vx = x/t = 15/0.31298 = 47.926 m/s

vy = gt = -9.80.31298 = -3.067 m/s

Initial speed of the arrow:

v = sqr(vx^2 + vy^2)

v = sqr(47.926^2+( -3.067^2)) = 48.02 m /s

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