The sum of 3 consecutive integral numbers is 117. Find the numbers.?
The sum of three consecutive integers is 117. What are the numbers?
7 Answers
Dec 25, 2024
I think you mean Consecutive integers (integrals are calculus material)
So:
x + (x+1) + (x+2) = 117
3x + 3 = 117
3x = 114
x = 38
so, 38, 39, 40
x+(x+1)(x+2)=117
x+x+1+x+2=117
3x + 3 = 117
3x = 114
x = 38
38+1 = 39
38+2 = 40
Check 38+39+40 = 117
so three consecutive integral numbers are 38 ,39 and 40
Let the three consecutive numbers be n-1, n, n+1 then their sum is 3n i.e. 3n=117 therefore n=39 and the three numbers are 38, 39,40
a+b+c=117
b=a+1
c=a+2
a+a+1+a+2=117
Therefore: 3a=117-3=114 . So a=38
The numbers are: 38, 39 and 40.
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