The sum of three consecutive integers is 36. What is the largest of the three integers? The correct answer is 13.?
The sum of three consecutive integers is 36. What is the largest of these three integers? I believe the correct answer is 13. Could anyone confirm this?
9 Answers
called x the smaller of the three :
3x+3 = 36
x = 33/3 = 11
y = x+1 = 12
z = x+2 = 13
Let x be the largest.
Let x-1 be the next smaller.
Let x-2 be the smallest.
x + x-1 + x-2 = 36
3x – 3 = 36
3x = 39
x = 13
Answer:
The largest number is 13
Dec 27, 2024
The average, 12, is the middle one.
They are consecutive integers so the largest is 13.
n + (n + 1) + (n + 2) = 36
3n + 3 = 36
3n = 36 – 3
3n = 33
n = 11
n = 11
n + 1 = 11 + 1 = 12
n + 2 = 11 + 2 = 13 Largest Integer..
The largest integer is 13……Answer//
The sum of three consecutive integers is 36.
(x – 1) + x + (x + 1) = 36
13 is the largest of the three integers.
Three consecutive integers can be expressed like this:
x
x + 1
x + 2
“Sum” means addition, so the sum of three consecutive integers equaling 36 can be expressed like this:
x + (x + 1) + (x + 2) = 36
You should be able to run with that
Dec 31, 2024
Write an equation. Call the first integer x. So what’s the next consecutive integer? And the next? Add them all together. What do they equal? Solve the equation for x. That gives you the first integer. From that, you know the next 2 consecutive integers.
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