The unspecified currents in (Figure 1) are IA = 6 A and ID = 5 A . The directions of the currents are as noted.?
What are the values of currents IC and IB in the figure, given that the unspecified currents are IA = 6 A and ID = 5 A, with their directions indicated? Could someone explain this step-by-step? Thank you in advance!
(Note: The figure can be accessed via this link: https://session.masteringphysics.com/problemAsset/...)
1 Answers
This is example of Kirchoff's junction rule. Simply, the currents going into a junction must equal the currents leaving a junction.
At the left junction, we've got 7A going in. Going out, we've got Ia (6A) and Ic. So:
7 = 6 + Ic
Ic = 1 A
For the right junction, we've got Ic (1A) and Id (5A) going in, and Ib going out. So:
1 + 5 = Ib
Ib = 6 A
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