Shirley Windler
Dec 17, 2024
What element results if two protons and two neutrons are ejected from a radium nucleus?
What element is formed when a radium nucleus ejects two protons and two neutrons?
2 Answers
The result is Radon-222, Rn-222.
You start off with Radium, Ra, which consulting the periodic table has 88 protons (it’s element #88, which is the number of protons). This is assumed to be Ra-226 (the mass number of Ra is about 226). This means that Ra-226 has 226 (mass) – 88 (number of protons) = 138 neutrons. So, if Ra-226 loses its 2 protons, it becomes element # 86, which is Rn. It also lost 2 neutrons, so it goes from 138 neutrons to 136 neutrons. Adding 136 (# of neutrons) + 86 (# of protons) you get 222, which is the mass of the Rn atom. So, Rn-222.
Hope that helps!
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