What is Δn for the following equation in relating Kc to Kp? 2NH3(g) ↔ N2(g) + 3H2(g)?

Question

What is the change in the number of moles of gas (Δn) for the following equilibrium reaction, and how does it relate to the equilibrium constants Kc and Kp? 
2NH3(g) ↔ N2(g) + 3H2(g)

Anonymous · Accepted Answer

Δn = product gas moles – reactant gas moles = 4 – 2 = 2

Martin Hegmann · Answer

Δn = product – reactant = 2 – 4 = -2

Anonymous · Answer

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Shakira Kuhic PhD · Answer

for delta n it is always the moles of products minus the moles of reactants. The answer is -2

Anonymous

What is Δn for the following equation in relating Kc to Kp? 2NH3(g) ↔ N2(g) + 3H2(g)?

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